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Train Aptitude Question and Answer Hindi For Bank SSC:
Here I am going to share you with Train shortcuts here i am tell you how you can solve Train problems, quantitative aptitude problems within minutes. in this section we will tell you Train Problems ,train formula, train shortcuts, train short tricks With Solutions. Here we also provide you train quiz in this quiz total question will be 30 and total time will be 20 minutes. here you can practis aptitude aptitude test practice. so register with us and take online aptitude quiz.
Train Problem Short cuts
 Time taken by a train to cross a stationary point
 Time taken by a train to cross a stationary length
 Time taken by a train to cross a moving length
* km/hr – m/s conversion:
X km/hr = [X * (5/18)] m/s.
* m/s – km/hr conversion:
X m/s = [X * (18/5)] km/hr.
Train Problem Formula Remember Point
 Time taken by a train to cross a stationary point = train length/train speed
 Time taken by a train to cross a stationary length = (train length + stationary length)/train speed
 Time taken by a train to cross another train moving in the same direction = sum of length of the two trains/difference in their speeds
 Time taken by a train to cross another train moving towards it = sum of length of the two trains/sum of their speeds
 Time taken by a train of length 1 meter to pass a pole or a standing man or a signal post is equal to the time taken by the train to cover 1 meter.
 Time taken by a train of length 1 meters to pass a stationary object of length b meters is the time taken by the train to cover (1 + b) meters.
 Suppose two trains or two bodies are moving in the same direction at u m / s and v m/s, where u > v, then their relatives speed = (u – v) m / s.
 Suppose two trains or two bodies are moving in opposite directions at u m / s and v m/s, then their relative speed is = (u + v) m/s.
 If two trains of length a meters and b meters are moving in opposite directions at u m / s and v m/s, then time taken by the trains to cross each other = (a + b)/(u+v)sec.
 If two trains of length a meters and b meters are moving in the same direction at u m / s and v m / s, then the time taken by the faster train to cross the slower train = (a+b)/(uv) sec.
 If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then
(A’s speet) : (B’s speed) = (b1/2: a1/2).
Example:
1.If a train going at 90 kmph takes 28 seconds to go past a lamp post, but 80seconds to cross a platform, what is the length of (a) the train and (b) the platform?
90 kmph= (90 × 5/18) = 25 m/s.
Solution for (a):
Given the time to cross the lamp post as 28 seconds,
Formula:
(train length/25 )= 28 or train length = 700 m.
Solution for (b):
Given the time to cross the platform as 80 seconds,
Formula:
{(train length + platform length)/25 } = 80
or (train length + platform length) = 2000 m.
Since train length is 700 m, platform length = 1300 m or 1.3 km.
Example 2: How long does it take for a train of length 800 m moving at 80 kmph to cross a train of length 1200 m coming at a speed of 100 kmph from the opposite direction?
The relative speed = 80 + 100 (Moving opposite direction)
= 180 kmph = 50 m/s.
The distance to be covered = 800 + 1200 ( Sum of the train length)
= 2000 m.
Formula:
Time taken for crossing = 2000/50 (Time = Sum of the train length / Relative Speed) = 40 seconds.
Example 3:
Two trains of length 100m and 200m are 100m apart. They start moving towards each other on parallel tracks, at speed 54 kmph and 72 kmph. After how much time will the trains meet?
In this problem, we need to find the time taken by trains to meet each other. So no need to consider the train length.
Distance between the trains = 100m
Relative speed = 54+72 kmph (Trains are in opposite direction)
= 126 kmph = 35mps
Time taken = Distance/ Relative speed
= 100/35 = 20/7 seconds
Example 4:
Two trains of length 100m and 200m are 100m apart. They start moving towards each other on parallel tracks, at speed 54 kmph and 72 kmph. After how much time will the trains cross each other?
In this problem, we need to find the time taken by trains to cross each other. So we need to consider the train length and also distance between the trains.
Distance to be covered = 100+200 +100 (Train length 1 + Train length 2 +distance between them)
Relative Speed = 35 mps
Time taken = Distance/ Relative speed
= 400/35 = 80/7 seconds
Example 5:
Two trains of length 100m and 200m are 100m apart. They start moving towards each other on parallel tracks, at speed 54 kmph and 72 kmph. After how much time will the trains be 100m apart again ?
In this problem, Trains have to cross each other and then be at 100m apart.
For distance , we need to consider initial distance , train length and their final distance between them.
Relative Speed = 35 mps
Distance to be covered = 100+100+200+100 = 500m
Time taken = 500/35 = 100/7 seconds.
Single Train Questions (2 Types of questions) Train Tricks
Tricks 1:– What is the time taken by a train of length ‘L’ metres and travelling at a speed of ‘S’ to pass a pole or a standing man or a signal post or some stationary object?
Explanation
 The Question will contain length of the train ‘L’
 Train’s speed ‘S’ will be given in terms of either km/hr or m/sec.
If speed is given in terms of Km/hr, always remember to convert it to m/sec which can be done by this formula: =S x (5/18) m/sec
 You have to find the time taken by the train to pass the stationary object. Use this formula
Time taken to pass the object= L/S sec
Tricks 2: What is the time taken by a train of length ‘L’ metres and travelling at speed of ‘S’ to pass a pole or a standing man or a signal post or some stationary object of Length ‘M’?
Explanation
 The Question will contain length of the train ‘L’
 Length of the object ‘M’
 Train’s speed ‘S’ will be given in terms of either km/hr or m/sec.
If the speed is given in terms of Km/hr, always remember to convert it to m/sec which is done by this formula: =S x (5/18) m/sec
 You have to find the time taken by the train to pass the object of length ‘M’. Follow this procedure
 You know this: Time taken to pass the object= L/S sec
 Make changes to the above formula in this way…
Time taken to pass the object of length ‘M’ = (L+M)/S sec
Two Train Questions (3 Types)
Tricks 3: What is the taken by the two trains that are of length ‘a’ and ‘b’ respectively and travelling opposite to each other at a speed of ‘u’ and ‘v’ respectively to cross each other?
Explanation
 The Question will contain two trains and its lengths as; ‘a’ of the first train and ‘b’ of the second train.
 The speed of the trains will also be included as ‘u’ as speed of the first train and ‘v’ as the speed of the second train
If the speed is given in terms of Km/hr, always remember to convert it to m/sec which is done by this formula
For train 1: =u x (5/18) m/sec an
For train 2: = v x (5/18) m/sec
Or = (u+v) x (5/18) m/sec
 Now you have find out the time taken by the trains to cross each other; use this formula
= (a+b)/ (u+v) u+v is called as relative speed of trains travelling in opposite direction
Tricks: 4 What is the taken by the two trains that are of length ‘a’ and ‘b’ respectively and travelling in the same direction or parallel to each other at a speed of ‘u’ and ‘v’ respectively to cross each other?
Explanation
 The Question will contain two trains and its lengths as: ‘a’ of the first train and ‘b’ of the second train.
 The speed of the trains will also be included as ‘u’ as speed of the first train and ‘v’ as the speed of the second train
If the speed is given in terms of Km/hr, always remember to convert it to m/sec which is done by this formula
For train 1: =u x (5/18) m/sec and
For train 2: = v x (5/18) m/sec
Or
= (u+v) x (5/18) m/sec
 Now you have find out the time taken by the trains to cross each other;
 use this formula
= (a+b)/ (uv) uv is called as relative speed of trains travelling in opposite direction
Tricks 5:What is the time taken by the two trains that start at their points: A for the first train and B for the second train that travels at a speed of ‘u’ and ‘v’ respectively to reach their destination after crossing each other?
Explanation
 The Question will contain two trains and its’ Speed as: ‘u’ of the first train and ‘v’ of the second train.
 You have to find out the time taken by the trains to reach their destination after crossing each other.
 Use this formula (√v: √u)
Train Problem Quiz
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Question 1 of 30
1. Question
1 pointsA train is 100 meter long and is running at the speed of 30 km per hour. Find the time it will take to pass a man standing at a crossing.
Correct
Explanation:
As we need to get answer in seconds, so never forget to convert speed into meter per second.
Speed = 30 km/hr = 30* 5/18 m/sec
= 25/3 m/secDistance = length of train = 100 meter
Required time =
DistanceSpeed=100253=100∗325=12secIncorrect
Explanation:
As we need to get answer in seconds, so never forget to convert speed into meter per second.
Speed = 30 km/hr = 30* 5/18 m/sec
= 25/3 m/secDistance = length of train = 100 meter
Required time =
DistanceSpeed=100253=100∗325=12sec 
Question 2 of 30
2. Question
1 pointsA train is moving at a speed of 132 km/hour. If the length of the train is 110 meters, how long will it take to cross a railway platform 165 meters long.
Correct
Answer: Option B
Explanation:
As we need to calculate answer in seconds, so first convert speed into meter/sec.
we know 1 km/hr = 1*(5/18) m/sec
So, Speed = 132* (5/18) = 110/3 m/secDistance need to be covered in passing the platform =
Length of train + length of platform = 110 + 165
= 275 metersTime = Distance/Speed
=>Time=275∗3110=152=7.5secondsIncorrect
Answer: Option B
Explanation:
As we need to calculate answer in seconds, so first convert speed into meter/sec.
we know 1 km/hr = 1*(5/18) m/sec
So, Speed = 132* (5/18) = 110/3 m/secDistance need to be covered in passing the platform =
Length of train + length of platform = 110 + 165
= 275 metersTime = Distance/Speed
=>Time=275∗3110=152=7.5seconds

Question 3 of 30
3. Question
1 pointsIn what time will a train 100 meters long cross an electric pole, if its speed is 144 km/hr
Correct
Explanation:
First convert speed into m/sec
Speed = 144*(5/18) = 40 m/sec
Time = Distance/speed
= 100/40 = 2.5 secondsIncorrect
Explanation:
First convert speed into m/sec
Speed = 144*(5/18) = 40 m/sec
Time = Distance/speed
= 100/40 = 2.5 seconds 
Question 4 of 30
4. Question
1 pointsHow long does a train 110 meters long running at the speed of 72 km/hour take to cross a bridge 132 meters in length ?
Correct
Explanation:
Speed = 72 km/hour = 72*(5/18) m/sec
= 20 m/secTotal distance to be covered = 110+132 = 142 meters
Time = Distance/Speed
= 242/20 = 12.1 secondsIncorrect
Explanation:
Speed = 72 km/hour = 72*(5/18) m/sec
= 20 m/secTotal distance to be covered = 110+132 = 142 meters
Time = Distance/Speed
= 242/20 = 12.1 seconds 
Question 5 of 30
5. Question
1 pointsA train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length.
Correct
Explanation:
Speed = 45 Km/hr = 45*(5/18) m/sec
= 25/2 m/sec
Total distance = 360+140 = 500 meterTime = Distance/speed
=500∗225=40secondsIncorrect
Explanation:
Speed = 45 Km/hr = 45*(5/18) m/sec
= 25/2 m/sec
Total distance = 360+140 = 500 meterTime = Distance/speed
=500∗225=40seconds 
Question 6 of 30
6. Question
1 pointsA train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train
Correct
Explanation:
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train(Distance) = Speed * Time
=503∗9=150meter
Incorrect
Explanation:
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train(Distance) = Speed * Time
=503∗9=150meter

Question 7 of 30
7. Question
1 pointsLength of train is 130 meters and speed of train is 45 km/hour. This train can pass a bridge in 30 seconds, then find the length of the bridge
Correct
Explanation:
Let the length of bridge is X [as always we do :)]
Speed of train is = 45*(5/18) m/sec = 25/2 m/sec
Time = 30 secondsTotal distance = 130+x
We know Speed = distance/time
so,
130+x30=252=>2(130+x)=750x=245 meters130+x30=252=>2(130+x)=750x=245 metersIncorrect
Explanation:
Let the length of bridge is X [as always we do :)]
Speed of train is = 45*(5/18) m/sec = 25/2 m/sec
Time = 30 secondsTotal distance = 130+x
We know Speed = distance/time
so,
130+x30=252=>2(130+x)=750x=245 meters130+x30=252=>2(130+x)=750x=245 meters 
Question 8 of 30
8. Question
1 pointsSpeed of a goods train is 72 km/hr. This train crosses a 250 meter platform in 26 seconds. Then find the length of goods train
Correct
Explanation:
First convert speed from km/hr to m/sec
So, Speed = 72*(5/18) = 20 m/sec
Time = 26 secondsLet the length of the train be x meters.
We know, Distance = Speed*Time.
[you can remember this formula as remembering DUST = D*ST… Distance=Speed*Time]x+250 = 20*26
=> x = 270 metersSo length of the goods train is 270 meter
Incorrect
Explanation:
First convert speed from km/hr to m/sec
So, Speed = 72*(5/18) = 20 m/sec
Time = 26 secondsLet the length of the train be x meters.
We know, Distance = Speed*Time.
[you can remember this formula as remembering DUST = D*ST… Distance=Speed*Time]x+250 = 20*26
=> x = 270 metersSo length of the goods train is 270 meter

Question 9 of 30
9. Question
1 pointsA 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform.
Correct
Explanation:
Speed = Distance/time = 300/18 = 50/3 m/sec
Let the length of the platform be x meters
then
Distance=Speed∗Timex+300=503∗39=>3(x+300)=1950=>x=350 metersIncorrect
Explanation:
Speed = Distance/time = 300/18 = 50/3 m/sec
Let the length of the platform be x meters
then
Distance=Speed∗Timex+300=503∗39=>3(x+300)=1950=>x=350 meters 
Question 10 of 30
10. Question
1 pointsA train speeds past a pole in 15 seconds and a platform 100 meter long in 25 seconds. What is length of the train ?
Correct
Incorrect
Explanation:
Let the length of the train is x meter and Speed of the train is y meter/second
Then x/y = 15 [because distance/speed = time]
=> y = 15/x=>x+10025=x15x=150 meters=>x+10025=x15x=150 meters
Explanation:
Let the length of the train is x meter and Speed of the train is y meter/second
Then x/y = 15 [because distance/speed = time]
=> y = 15/x=>x+10025=x15x=150 meters=>x+10025=x15x=150 meters

Question 11 of 30
11. Question
1 pointsTwo trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ?
Correct
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
Length of the second train = 17y metres.
[because distance = speed*time]27x+17yx+y=23=>27x+17y=23x+23y=>4x=6y=>xy=6427x+17yx+y=23=>27x+17y=23x+23y=>4x=6y=>xy=64
Incorrect
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
Length of the second train = 17y metres.
[because distance = speed*time]27x+17yx+y=23=>27x+17y=23x+23y=>4x=6y=>xy=6427x+17yx+y=23=>27x+17y=23x+23y=>4x=6y=>xy=64

Question 12 of 30
12. Question
1 pointsTwo trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is ?
Correct
Explanation:
Let the length of each train is x meter
Distance will be x+x = 2xRelative Speed = 4636 = 10 km/hr
= 10*(5/18) = 25/9 m/secDistance = Speed*Time
2x=259∗362x=100=>x=502x=259∗362x=100=>x=50
Incorrect
Explanation:
Let the length of each train is x meter
Distance will be x+x = 2xRelative Speed = 4636 = 10 km/hr
= 10*(5/18) = 25/9 m/secDistance = Speed*Time
2x=259∗362x=100=>x=502x=259∗362x=100=>x=50

Question 13 of 30
13. Question
1 pointsA 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Correct
Explanation:
As trains are running in opposite directions so their relative speed will get added
So, Relative speed = 120 +80 = 200 kmph
= 200*(5/18) = 500/9 m/secLet the length of other train is x meter then
x+2709=5009=>x+270=500=>x=230x+2709=5009=>x+270=500=>x=230
Incorrect
Explanation:
As trains are running in opposite directions so their relative speed will get added
So, Relative speed = 120 +80 = 200 kmph
= 200*(5/18) = 500/9 m/secLet the length of other train is x meter then
x+2709=5009=>x+270=500=>x=230x+2709=5009=>x+270=500=>x=230

Question 14 of 30
14. Question
1 pointsTwo trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other, is
Correct
Explanation:
Relative Speed = 60+40 = 100 kmph
= 100*(5/18) = 250/9 m/secDistance = 140+160 = 300 meters
Time = Distance/Speed
300∗9250=545=10.8 seconds300∗9250=545=10.8 seconds
Incorrect
Explanation:
Relative Speed = 60+40 = 100 kmph
= 100*(5/18) = 250/9 m/secDistance = 140+160 = 300 meters
Time = Distance/Speed
300∗9250=545=10.8 seconds300∗9250=545=10.8 seconds

Question 15 of 30
15. Question
1 pointsTwo trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train ?
Correct
Explanation:
As Trains are moving in same direction,
So, Relative Speed = 4020 = 20 kmph
= 20*(5/18) = 50/9 m/secLength of Train= Speed * Time
Length=509∗5=2509=2779
Incorrect
Explanation:
As Trains are moving in same direction,
So, Relative Speed = 4020 = 20 kmph
= 20*(5/18) = 50/9 m/secLength of Train= Speed * Time
Length=509∗5=2509=2779

Question 16 of 30
16. Question
1 pointsTwo trains are running in opposite directions in the same speed. The length of each train is 120 meter. If they cross each other in 12 seconds, the speed of each train (in km/hr) is
Correct
 Explanation:
Distance covered = 120+120 = 240 m
Time = 12 sLet the speed of each train = x.
Then relative velocity = x+x = 2x2x = distance/time = 240/12 = 20 m/s
Speed of each train = x = 20/2 = 10 m/s
= 10*18/5 km/hr = 36 km/hr
Incorrect
Explanation:
Distance covered = 120+120 = 240 m
Time = 12 sLet the speed of each train = x.
Then relative velocity = x+x = 2x2x = distance/time = 240/12 = 20 m/s
Speed of each train = x = 20/2 = 10 m/s
= 10*18/5 km/hr = 36 km/hr

Question 17 of 30
17. Question
1 pointsA train, 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel ?
Correct
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 secondsSpeed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
=>800+x=653∗60=>800+x=20∗65=1300=>x=1300−800=500=>800+x=653∗60=>800+x=20∗65=1300=>x=1300−800=500Incorrect
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 secondsSpeed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
=>800+x=653∗60=>800+x=20∗65=1300=>x=1300−800=500=>800+x=653∗60=>800+x=20∗65=1300=>x=1300−800=500 
Question 18 of 30
18. Question
1 pointsHow many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr
Correct
Explanation:
Relative Speed = 633 = 60 Km/hr
= 60 *(5/18) = 50/3 m/secTime taken to pass the man will ne
500∗350=30 secondsIncorrect
Explanation:
Relative Speed = 633 = 60 Km/hr
= 60 *(5/18) = 50/3 m/secTime taken to pass the man will ne
500∗350=30 seconds 
Question 19 of 30
19. Question
1 pointsA jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?
Correct
Explanation:
Speed of train relative to jogger = (459) = 36 kmph
= 36*(5/18) = 10 m/secDistance to cover = 240 + 120 = 360 metres
Time = Distance/Speed
So,
Time=36010=36 SecondsIncorrect
Explanation:
Speed of train relative to jogger = (459) = 36 kmph
= 36*(5/18) = 10 m/secDistance to cover = 240 + 120 = 360 metres
Time = Distance/Speed
So,
Time=36010=36 SecondsExplanation:
Speed of train relative to jogger = (459) = 36 kmph
= 36*(5/18) = 10 m/secDistance to cover = 240 + 120 = 360 metres
Time = Distance/Speed
So,
Time=36010=36 Seconds 
Question 20 of 30
20. Question
1 pointsTwo trains 140 metre and 160 metre long run at the speed of 60 km/hr and 40 km/hr respectively in opposite direction on parallel tracks. What time these will take to cross each other ?
Correct
Explanation:
Relative Speed = 60+40 = 100 Kmph
= 100*(5/18) = 250/9 m/secDistance to be covered = 140 + 160 = 300 metres
Time = Distance/Speed
Time=300∗9250=545=10.8 seconds
Incorrect
Explanation:
Relative Speed = 60+40 = 100 Kmph
= 100*(5/18) = 250/9 m/secDistance to be covered = 140 + 160 = 300 metres
Time = Distance/Speed
Time=300∗9250=545=10.8 seconds

Question 21 of 30
21. Question
1 pointsA train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. Find the length of train ?
Correct
Explanation:
First person speed = 2*(5/18) = 5/9 m/sec
Second person speed = 4*(5/18) = 10/9 m/secLet the length of train is x metre and speed is y m/sec
then,
xy−59=9=>9y−5=x=>9y−x=5…..(i)Also,xy−109=1090y−9x=100…..(ii)from (i) and (ii), we get,x=50xy−59=9=>9y−5=x=>9y−x=5…..(i)Also,xy−109=1090y−9x=100…..(ii)from (i) and (ii), we get,x=50
Incorrect
Explanation:
First person speed = 2*(5/18) = 5/9 m/sec
Second person speed = 4*(5/18) = 10/9 m/secLet the length of train is x metre and speed is y m/sec
then,
xy−59=9=>9y−5=x=>9y−x=5…..(i)Also,xy−109=1090y−9x=100…..(ii)from (i) and (ii), we get,x=50xy−59=9=>9y−5=x=>9y−x=5…..(i)Also,xy−109=1090y−9x=100…..(ii)from (i) and (ii), we get,x=50

Question 22 of 30
22. Question
1 pointsA train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Correct
Explanation:
Speed= 60 x 5 m/sec = 50 m/sec.
18 3
Length of the train = (Speed x Time) = 50 x 9 m = 150 m.
3Incorrect
Explanation:
Speed= 60 x 5 m/sec = 50 m/sec.
18 3
Length of the train = (Speed x Time) = 50 x 9 m = 150 m.
3 
Question 23 of 30
23. Question
1 pointsA train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Correct
Speed of the train relative to man = 125 m/sec
10
= 25 m/sec.
2
= 25 x 18 km/hr
2 5
= 45 km/hr.Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45 x = 50 km/hr.
Incorrect
Speed of the train relative to man = 125 m/sec
10
= 25 m/sec.
2
= 25 x 18 km/hr
2 5
= 45 km/hr.Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45 x = 50 km/hr.

Question 24 of 30
24. Question
1 pointsThe length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Correct
Explanation:
Speed = 45 x 5 m/sec = 25 m/sec.
18 2
Time = 30 sec.Let the length of bridge be x metres.
Then, 130 + x = 25
30 2
2(130 + x) = 750x = 245 m
Incorrect
Explanation:
Speed = 45 x 5 m/sec = 25 m/sec.
18 2
Time = 30 sec.Let the length of bridge be x metres.
Then, 130 + x = 25
30 2
2(130 + x) = 750x = 245 m

Question 25 of 30
25. Question
1 pointsTwo trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Correct
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y = 23
x+ y
27x + 17y = 23x + 23y4x = 6y
x = 3 .
y 2Incorrect
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y = 23
x+ y
27x + 17y = 23x + 23y4x = 6y
x = 3 .
y 2 
Question 26 of 30
26. Question
1 pointsA train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Correct
Explanation:
Speed = 54 x 5 m/sec = 15 m/sec. 18 Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, x + 300 = 15 36 x + 300 = 540
x = 240 m.
Incorrect
Explanation:
Speed = 54 x 5 m/sec = 15 m/sec. 18 Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, x + 300 = 15 36 x + 300 = 540
x = 240 m.

Question 27 of 30
27. Question
1 pointsA train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Correct
Explanation:
Speed = 240 m/sec = 10 m/sec. 24 Required time = 240 + 650 sec = 89 sec. 10 Incorrect
Explanation:
Speed = 240 m/sec = 10 m/sec. 24 Required time = 240 + 650 sec = 89 sec. 10 
Question 28 of 30
28. Question
1 pointsTwo trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: Correct
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 – 36) km/hr
= 10 x 5 m/sec 18 = 25 m/sec 9 2x = 25 36 9 2x = 100
x = 50.
Incorrect
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 – 36) km/hr
= 10 x 5 m/sec 18 = 25 m/sec 9 2x = 25 36 9 2x = 100
x = 50.

Question 29 of 30
29. Question
1 pointsA train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long? Correct
Explanation:
Formula for converting from km/hr to m/s: X km/hr = X x 5 m/s. 18 Therefore, Speed = 45 x 5 m/sec = 25 m/sec. 18 2 Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = Distance Speed Required time = 500 x 2 sec = 40 sec. 25 Incorrect
Explanation:
Formula for converting from km/hr to m/s: X km/hr = X x 5 m/s. 18 Therefore, Speed = 45 x 5 m/sec = 25 m/sec. 18 2 Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = Distance Speed Required time = 500 x 2 sec = 40 sec. 25 
Question 30 of 30
30. Question
1 pointsTwo trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: Correct
Answer: Option C
Explanation:
Relative speed = (60+ 90) km/hr
= 150 x 5 m/sec 18 = 125 m/sec. 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = 2000 x 3 sec = 48 sec. 125 Incorrect
Answer: Option C
Explanation:
Relative speed = (60+ 90) km/hr
= 150 x 5 m/sec 18 = 125 m/sec. 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = 2000 x 3 sec = 48 sec. 125