Train Aptitude Question and Answer For Bank SSC

Train Aptitude  Question and Answer Hindi For Bank SSC:-

Here I am going to share you with Train  shortcuts  here i am tell you how you can solve Train problems, quantitative aptitude problems within minutes. in this section we will tell you Train  Problems ,train formula, train shortcuts, train short tricks With Solutions. Here we also provide you train quiz in this quiz total question will be 30 and total time will be 20 minutes. here you can practis aptitude aptitude test practice. so register with us and take online aptitude quiz.

Train Problem Short cuts

  1. Time taken by a train to cross a stationary point
  2. Time taken by a train to cross a stationary length
  3. Time taken by a train to cross a moving length

* km/hr – m/s conversion:

X km/hr = [X * (5/18)] m/s.

* m/s – km/hr conversion:

X m/s = [X * (18/5)] km/hr.

Train Problem Formula Remember Point

  • Time taken by a train to cross a stationary point = train length/train speed
  • Time taken by a train to cross a stationary length = (train length + stationary length)/train speed
  • Time taken by a train to cross another train moving in the same direction = sum of length of the two trains/difference in their speeds
  • Time taken by a train to cross another train moving towards it = sum of length of the two trains/sum of their speeds
  • Time taken by a train of length 1 meter to pass a pole or a standing man or a signal post is equal to the time taken by the train to cover 1 meter.
  • Time taken by a train of length 1 meters to pass a stationary object of length b meters is the time taken by the train to cover (1 + b) meters.
  • Suppose two trains or two bodies are moving in the same direction at u m / s and v m/s, where u > v, then their relatives speed = (u – v) m / s.
  • Suppose two trains or two bodies are moving in opposite directions at u m / s and v m/s, then their relative speed is = (u + v) m/s.
  • If two trains of length a meters and b meters are moving in opposite directions at u m / s and v m/s, then time taken by the trains to cross each other = (a + b)/(u+v)sec.
  • If two trains of length a meters and b meters are moving in the same direction at u m / s and v m / s, then the time taken by the faster train to cross the slower train = (a+b)/(u-v) sec.
  • If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then
    (A’s speet) : (B’s speed) = (b1/2: a1/2).

Example:

1.If a train going at 90 kmph takes 28 seconds to go past a lamp post, but 80seconds to cross a platform, what is the length of (a) the train and (b) the platform?

90 kmph= (90 × 5/18) = 25 m/s.

Solution for (a):

Given the time to cross the lamp post as 28 seconds,

Formula:

(train length/25 )= 28 or train length = 700 m. 

Solution for (b):

Given the time to cross the platform as 80 seconds,

Formula:

{(train length + platform length)/25 } = 80

or (train length + platform length) = 2000 m.

Since train length is 700 m, platform length = 1300 m or 1.3 km.

Example 2:- How long does it take for a train of length 800 m moving at 80 kmph to cross a train of length 1200 m coming at a speed of 100 kmph from the opposite direction?

The relative speed = 80 + 100 (Moving opposite direction)

= 180 kmph = 50 m/s.

The distance to be covered = 800 + 1200 ( Sum of the train length)

= 2000 m.

Formula:

Time taken for crossing = 2000/50 (Time = Sum of the train length / Relative Speed)         = 40 seconds.

Example 3:

Two trains of length 100m and 200m are 100m apart. They start moving towards each other on parallel tracks, at speed 54 kmph and 72 kmph. After how much time will the trains meet?

In this problem, we need to find the time taken by trains to meet each other. So no need to consider the train length.

Distance between the trains = 100m

Relative speed = 54+72 kmph (Trains are in opposite direction)

= 126 kmph = 35mps

Time taken = Distance/ Relative speed

= 100/35 = 20/7 seconds

Example 4:

Two trains of length 100m and 200m are 100m apart. They start moving towards each other on parallel tracks, at speed 54 kmph and 72 kmph. After how much time will the trains cross each other?

In this problem, we need to find the time taken by trains to cross each other. So we need to consider the train length and also distance between the trains.

Distance to be covered = 100+200 +100 (Train length 1 + Train length 2 +distance between them)

Relative Speed = 35 mps

Time taken = Distance/ Relative speed

= 400/35 = 80/7 seconds

Example 5:

Two trains of length 100m and 200m are 100m apart. They start moving towards each other on parallel tracks, at speed 54 kmph and 72 kmph. After how much time will the trains be 100m apart again ?

In this problem, Trains have to cross each other and then be at 100m apart.

For distance , we need to consider initial distance , train length and their final distance between them.

Relative Speed = 35 mps

Distance to be covered = 100+100+200+100 = 500m

Time taken = 500/35 = 100/7 seconds.

Single Train Questions (2 Types of questions) Train Tricks 

Tricks 1:– What is the time taken by a train of length ‘L’ metres and travelling at a speed of ‘S’ to pass a pole or a standing man or a signal post or some stationary object?

Explanation

  • The Question will contain length of the train ‘L’
  • Train’s speed ‘S’ will be given in terms of either km/hr or m/sec.

If speed is given in terms of Km/hr, always remember to convert  it to m/sec which can be done    by this formula: =S x (5/18) m/sec

  • You have to find the time taken by the train to pass the stationary object. Use this formula

Time taken to pass the object= L/S sec

Tricks 2: What is the time taken by a train of length ‘L’ metres and travelling at speed of ‘S’ to pass a pole or a standing man or a signal post or some stationary object of Length ‘M’?

Explanation

  • The Question will contain length of the train ‘L’
  • Length of the object ‘M’
  • Train’s speed ‘S’ will be given in terms of either km/hr or m/sec.

If the speed is given in terms of Km/hr, always remember to convert it to m/sec which is done   by this formula: =S x (5/18) m/sec

  • You have to find the time taken by the train to pass the object of length ‘M’. Follow this procedure
  1. You know this: Time taken to pass the object= L/S sec
  2. Make changes to the above formula in this way…

Time taken to pass the object of length ‘M’ = (L+M)/S sec

Two Train Questions (3 Types)

Tricks 3:- What is the taken by the two trains that are of length ‘a’ and ‘b’ respectively and travelling opposite to each other at a speed of ‘u’ and ‘v’ respectively to cross each other?

Explanation

  • The Question will contain two trains and its lengths as; ‘a’ of the first train and ‘b’ of the second train.
  • The speed of the trains will also be included  as ‘u’ as speed of the first train and ‘v’ as the speed of the second train

If the speed is given in terms of Km/hr, always remember to convert it to m/sec which is done by this formula

For train 1:      =u x (5/18) m/sec an

For train 2:     = v x (5/18) m/sec

Or = (u+v) x (5/18) m/sec

  • Now you have find out the time taken by the trains to cross each other; use this formula

= (a+b)/ (u+v) u+v is called as relative speed of trains travelling in opposite direction

 

Tricks:- 4 What is the taken by the two trains that are of length ‘a’ and ‘b’ respectively and travelling in the same direction or parallel to each other at a speed of ‘u’ and ‘v’ respectively to cross each other?

Explanation

  • The Question will contain two trains and its lengths as: ‘a’ of the first train and ‘b’ of the second train.
  • The speed of the trains will also be included  as ‘u’ as speed of the first train and ‘v’ as the speed of the second train

If the speed is given in terms of Km/hr, always remember to convert it to m/sec which is done by   this formula

For train 1: =u x (5/18) m/sec and

            For train 2: = v x (5/18) m/sec

Or

= (u+v) x (5/18) m/sec

  • Now you have find out the time taken by the trains to cross each other;
  • use this formula

 = (a+b)/ (u-v)   u-v is called as relative speed of trains travelling in opposite direction

 

Tricks 5:-What is the time taken by the two trains that start at their points: A for the first train and B for the second train that travels at a speed of ‘u’ and ‘v’ respectively to reach their destination after crossing each other?

Explanation

  • The Question will contain two trains and its’ Speed as: ‘u’ of the first train and ‘v’ of the second train.
  • You have to find out the time taken by the trains to reach their destination after crossing each other.
  • Use this formula  (√v: √u)

Train Problem Quiz

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