Time and Distance Questions Answers:
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Time and Distance Formula :
Time and Distance Shortcuts:
Time and Distance Tricks 1: If a person travels half a distance in a journey at x km/hr and remaining half at the speed of y km/hr, the average speed of the whole journey is given by:
Example 1
A person travels half of journey at the speed of 30 km/hr and the next half at a speed of 15 km/hr. What is the average speed of the person during the whole journey?
Here; x= 30 and y= 15 Putting the in above formula the Answer will be= 20 km/hr
Time and Distance Tricks 2: If a person travels three equal distances in a journey at a speed of x km/hr, y km/hr and z km/hr. The average speed is given by:
Example 2
Rajesh starts from Faizabad to Lucknow a distance of about 300 kms. He divided his journey into a distance of thee equal parts in terms of distance and covered them with the speed of 30 km/hr, 60 km/hr and 90 km/hr, calculate his average speed during the journey:
Here: x= 30, y= 60, z= 90. Putting the values we get: Answer= 49.09 km/hr
Time and Distance Tricks 3: If a person travels Mth part of a distance at x km/hr, Nth part at y km/hr and the remaining Pth part at z km/hr, Then his average speed in km/hr is given by:
If instead of proportion, the parts of the distance are given in percentage i.e. M%, N% and P% respectively, then the formula becomes:
Example 3
Hari travels 20% of a distance at an average speed of 20 km/hr, next 30% distance at an average speed of 30 km/hr and the remaining 50% of distance at the average speed of 50 km/hr. Find his average speed during the whole journey.
Sol: Here M=20, N=30 and P= 50 also x= 20, y= 30 and z= 50
Putting the values we get: Answer =33.33 km/hr
Time and Distance Tricks 4: If a car does a journey in ‘T’ hrs, the first half at ‘a’ km/hr and the second half at ‘b’ km/hr. The total distance covered by the car:
(2 x Time x a x b ) / (a + b).
Example: A motorcar does a journey in 10 hrs, the first half at 21 kmph and the second half at 24 kmph. Find the distance?
Sol: Distance = (2 x 10 x 21 x 24) / (21+24)
= 10080 / 45
Answer = 224 km.
Time and Distance Tricks 5 .If a person goes from ‘A’ to ‘B’ at a speed of ‘a’ kmph and returns at a speed of ‘b’ kmph and takes ‘T’ hours in all, then the distance between the A and B:
= Total time taken x (Product of the two Speeds / Addition of the two speeds)
Example: A boy goes to school at a speed of 3 kmph and returns to the village at a speed of 2 kmph. If he takes 5 hrs in all, what is the distance between the village and the school?
Sol: Let the required distance be x km.
Then time taken during the first journey = x/3 hr.
and time taken during the second journey = x/2 hr.
x/3 + x/2 = 5 => (2x + 3x) / 6 = 5
=> 5x = 30.
=> x = 6
required distance = 6 km.
Time And Distance Solved Example
Ex .An aeroplane files along the four sides of a square at the speeds of 200,400,600 and 800km/hr.Find the average speed of the plane around the field.
Sol. :
Let each side of the square be x km and let the average speed of the plane around the field by y km per hour then ,
x/200+x/400+x/600+x/800=4x/y=25x/2500=4x/y=y=(2400*4/25)=384 hence average speed =384 km/hr
Ex. If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
Sol. Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5x/6=1/5<=>6x5x=6 =x=6
Hence, the required distance is 6 km
Ex. A and B are two stations 390 km apart. A train starts from A at 10 a.m. and travels towards B at 65 kmph. Another train starts from B at 11 a.m. and travels towards A at 35 kmph. At what time do they meet?
Sol. Suppose they meet x hours after 10 a.m. Then,
(Distance moved by first in x hrs) + [Distance moved by second in (x1) hrs]=390.
65x + 35(x1) = 390 => 100x = 425 => x = 17/4
So, they meet 4 hrs.15 min. after 10 a.m i.e., at 2.15 p.m.
Ex. I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
Sol. Let the distance be x km. Then,
( Time taken to walk x km) + (time taken to ride x km) =37 min.
( Time taken to walk 2x km ) + ( time taken to ride 2x km )= 74 min.
But, the time taken to walk 2x km = 55 min.
Time taken to ride 2x km = (7455)min =19 min.
Time and Distance Quiz
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Question 1 of 30
1. Question
How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr
Correct
Explanation:
We know that,Time=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115minTime=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115min
Incorrect
Explanation:
We know that,Time=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115minTime=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115min

Question 2 of 30
2. Question
A cyclist covers a distance of 750 meter in 2 minutes 30 seconds. What is the speed in km/hr of cyclist
Correct
Explanation:
Speed=DistanceTimeDistance=750meterTime=2 min 30 sec=150secSpeed=750150=5m/sec=>5∗185km/hr=18km/hrSpeed=DistanceTimeDistance=750meterTime=2 min 30 sec=150secSpeed=750150=5m/sec=>5∗185km/hr=18km/hrIncorrect
Explanation:
Speed=DistanceTimeDistance=750meterTime=2 min 30 sec=150secSpeed=750150=5m/sec=>5∗185km/hr=18km/hrSpeed=DistanceTimeDistance=750meterTime=2 min 30 sec=150secSpeed=750150=5m/sec=>5∗185km/hr=18km/hr 
Question 3 of 30
3. Question
A car moves at 80 km/hr. What is the speed of the car in meters per second ?
Correct
Explanation:
Speed=(80∗518)m/sec=2009m/sec=2229msecSpeed=(80∗518)m/sec=2009m/sec=2229msecIncorrect
Explanation:
Speed=(80∗518)m/sec=2009m/sec=2229msecSpeed=(80∗518)m/sec=2009m/sec=2229msec 
Question 4 of 30
4. Question
An athlete runs 200 meters in 24 seconds. His speed is ?
Correct
Explanation:
Speed=DistanceTime=20024m/sec=253m/sec253∗185km/hr=30km/hrSpeed=DistanceTime=20024m/sec=253m/sec253∗185km/hr=30km/hrIncorrect
Explanation:
Speed=DistanceTime=20024m/sec=253m/sec253∗185km/hr=30km/hrSpeed=DistanceTime=20024m/sec=253m/sec253∗185km/hr=30km/hr 
Question 5 of 30
5. Question
A person crosses a 600 meter long street in 5 minutes. What is the speed in Km/hr
Correct
Explanation:
Two things to give attention on this question.
First time is in minutes, we need to change it to seconds to get speed in m/sec, thenwe need to get the final answer in km/hr.
So lets solve this.Speed=DistanceTimeDistance=650meterTime=5 minutes=300secSpeed=600300=2m/sec=>2∗185km/hr=7.2km/hrSpeed=DistanceTimeDistance=650meterTime=5 minutes=300secSpeed=600300=2m/sec=>2∗185km/hr=7.2km/hr
Incorrect
Explanation:
Two things to give attention on this question.
First time is in minutes, we need to change it to seconds to get speed in m/sec, thenwe need to get the final answer in km/hr.
So lets solve this.Speed=DistanceTimeDistance=650meterTime=5 minutes=300secSpeed=600300=2m/sec=>2∗185km/hr=7.2km/hrSpeed=DistanceTimeDistance=650meterTime=5 minutes=300secSpeed=600300=2m/sec=>2∗185km/hr=7.2km/hr

Question 6 of 30
6. Question
A man is walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge is
Correct
Explanation:
We need to get the answer in meters. So we will first of change distance from km/hour to meter/sec by multiplying it with 5/18 and also change 15 minutes to seconds by multiplying it with 60.
Speed=5∗518=2518m/secTime=15∗60seconds=900secondsDistance=Time∗SpeedDistance=2518∗900=1250meterSpeed=5∗518=2518m/secTime=15∗60seconds=900secondsDistance=Time∗SpeedDistance=2518∗900=1250meterIncorrect
Explanation:
We need to get the answer in meters. So we will first of change distance from km/hour to meter/sec by multiplying it with 5/18 and also change 15 minutes to seconds by multiplying it with 60.
Speed=5∗518=2518m/secTime=15∗60seconds=900secondsDistance=Time∗SpeedDistance=2518∗900=1250meterSpeed=5∗518=2518m/secTime=15∗60seconds=900secondsDistance=Time∗SpeedDistance=2518∗900=1250meter 
Question 7 of 30
7. Question
A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
Correct
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmphIncorrect
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph 
Question 8 of 30
8. Question
Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
Correct
Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrsIncorrect
Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs 
Question 9 of 30
9. Question
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?
Correct
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54) hour
= (1/6)*60 minutes
= 10 minutesIncorrect
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54) hour
= (1/6)*60 minutes
= 10 minutes 
Question 10 of 30
10. Question
2 trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds ?
Correct
Explanation:
We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9Incorrect
Explanation:
We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9 
Question 11 of 30
11. Question
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Correct
Explanation:
Let time taken to travel the first half = x hr
Then time taken to travel the second half = (10 – x) hrDistance covered in the the first half = 21x [because, distance = time*speed]
Distance covered in the the second half = 24(10 – x)Distance covered in the the first half = Distance covered in the the second half
So,
21x = 24(10 – x)
=> 45x = 240
=> x = 16/3Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]
Incorrect
Explanation:
Let time taken to travel the first half = x hr
Then time taken to travel the second half = (10 – x) hrDistance covered in the the first half = 21x [because, distance = time*speed]
Distance covered in the the second half = 24(10 – x)Distance covered in the the first half = Distance covered in the the second half
So,
21x = 24(10 – x)
=> 45x = 240
=> x = 16/3Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]

Question 12 of 30
12. Question
A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot?
Correct
Explanation:
Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 – x) hrDistance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9x) = 61
=> 5x = 20
=> x = 4So distance traveled on foot = 4(4) = 16 km
Incorrect
Explanation:
Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 – x) hrDistance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9x) = 61
=> 5x = 20
=> x = 4So distance traveled on foot = 4(4) = 16 km

Question 13 of 30
13. Question
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. What is the duration of the flight ?
Correct
Explanation:
Let the duration of the flight be x hours.
Then
600x−600x+12=200600x−12002x+1=200x(2x+1)=32×2+x−3=0=>(2x+3)(x−1)=0600x−600x+12=200600x−12002x+1=200x(2x+1)=32×2+x−3=0=>(2x+3)(x−1)=0
Neglecting the negative value for x we get x = 1Incorrect
Explanation:
Let the duration of the flight be x hours.
Then
600x−600x+12=200600x−12002x+1=200x(2x+1)=32×2+x−3=0=>(2x+3)(x−1)=0600x−600x+12=200600x−12002x+1=200x(2x+1)=32×2+x−3=0=>(2x+3)(x−1)=0
Neglecting the negative value for x we get x = 1 
Question 14 of 30
14. Question
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average speed for first 320 km of tour.
Correct
Explanation:
We know Time = Distance/speed
So total time taken =
(16064+16080)=92hours Time taken for 320 Km = 320∗29=71.11km/hr(16064+16080)=92hours Time taken for 320 Km = 320∗29=71.11km/hr
Incorrect
Explanation:
We know Time = Distance/speed
So total time taken =
(16064+16080)=92hours Time taken for 320 Km = 320∗29=71.11km/hr(16064+16080)=92hours Time taken for 320 Km = 320∗29=71.11km/hr

Question 15 of 30
15. Question
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Correct
Incorrect

Question 16 of 30
16. Question
A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?
Correct
Explanation:
Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hrAverage speed =
2xyx+y=2∗40∗6040+60=4800100=48Km/hr2xyx+y=2∗40∗6040+60=4800100=48Km/hrIncorrect
Explanation:
Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hrAverage speed =
2xyx+y=2∗40∗6040+60=4800100=48Km/hr2xyx+y=2∗40∗6040+60=4800100=48Km/hr

Question 17 of 30
17. Question
The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
Correct
Explanation:
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x1) hrs]
= 330
So, 60x+75(x1) = 330x=3.
So,they meet at (8+3). i.e 11a.m.
Incorrect
Explanation:
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x1) hrs]
= 330
So, 60x+75(x1) = 330x=3.
So,they meet at (8+3). i.e 11a.m.

Question 18 of 30
18. Question
A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
Correct
Explanation:
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40*50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2*60 = 120 km/hourIncorrect
Explanation:
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40*50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2*60 = 120 km/hour 
Question 19 of 30
19. Question
A train traveled at an average speed of 100 km/hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point.
Correct
Explanation:
Time taken to cover 600 km = 6 hours [because train speed is 100 km/hr]
Number of stops =
begin{aligned}
frac{600}{75} – 1 = 7 \
text{Total time on stops =}7*3 = 21 minsend{aligned}
Total time taken by train = 6 hours 21 minsIncorrect
Explanation:
Time taken to cover 600 km = 6 hours [because train speed is 100 km/hr]
Number of stops =
begin{aligned}
frac{600}{75} – 1 = 7 \
text{Total time on stops =}7*3 = 21 minsend{aligned}
Total time taken by train = 6 hours 21 mins 
Question 20 of 30
20. Question
A person travels equal distances with speed of 3 km/hr, 4 km/hr and 5 km/hr and takes a total of 47 minutes. Find the total distance
Correct
Explanation:
Let the distance be 3x km,
then,x3+x4+x5=476047×60=4760x=1×3+x4+x5=476047×60=4760x=1
So total distance = 3*1 = 3 KmIncorrect
Explanation:
Let the distance be 3x km,
then,x3+x4+x5=476047×60=4760x=1×3+x4+x5=476047×60=4760x=1
So total distance = 3*1 = 3 Km 
Question 21 of 30
21. Question
A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start at same point at 7:30 am. They shall first cross each other at ?
Correct
Explanation:
Relative speed between two = 61 = 5 round per hour
They will cross when one round will complete with relative speed,
which is 1/5 hour = 12 mins.So 7:30 + 12 mins = 7:42
Incorrect
Explanation:
Relative speed between two = 61 = 5 round per hour
They will cross when one round will complete with relative speed,
which is 1/5 hour = 12 mins.So 7:30 + 12 mins = 7:42

Question 22 of 30
22. Question
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
Correct
Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes = 160∗6=110=100meters160∗6=110=100meters
So distance between them after 6 minutes = 200 – 100
= 100 metersIncorrect
Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes = 160∗6=110=100meters160∗6=110=100meters
So distance between them after 6 minutes = 200 – 100
= 100 meters 
Question 23 of 30
23. Question
The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
Correct
Explanation:
Let the speeds of two trains be 7X and 8X km/hr.
8X=4004=>X=12.5Km/hr8X=4004=>X=12.5Km/hr
So speed of first train is 12.5*7 = 87.5 km/hrIncorrect
Explanation:
Let the speeds of two trains be 7X and 8X km/hr.
8X=4004=>X=12.5Km/hr8X=4004=>X=12.5Km/hr
So speed of first train is 12.5*7 = 87.5 km/hr 
Question 24 of 30
24. Question
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Correct
Explanation:
Speed = 600 m/sec. 5 x 60 = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr 5 = 7.2 km/hr.
Incorrect
Explanation:
Speed = 600 m/sec. 5 x 60 = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr 5 = 7.2 km/hr.

Question 25 of 30
25. Question
An aero plane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of
Correct
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1200 x 3 km/hr = 720 km/hr. 5 Incorrect
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1200 x 3 km/hr = 720 km/hr. 5 
Question 26 of 30
26. Question
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Correct
Explanation:
Let the actual distance travelled be x km.
Then, x = x + 20 10 14 14x = 10x + 200
4x = 200
x = 50 km.
Incorrect
Explanation:
Let the actual distance travelled be x km.
Then, x = x + 20 10 14 14x = 10x + 200
4x = 200
x = 50 km.

Question 27 of 30
27. Question
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Correct
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = 150 x = 3 x kmph. 100 2 75 – 75 = 125 x (3/2)x 10 x 60 75 – 50 = 5 x x 24 x = 25 x24 = 120 kmph. 5 Incorrect
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = 150 x = 3 x kmph. 100 2 75 – 75 = 125 x (3/2)x 10 x 60 75 – 50 = 5 x x 24 x = 25 x24 = 120 kmph. 5 
Question 28 of 30
28. Question
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Correct
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9 x 60 min = 10 min. 54 Incorrect
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9 x 60 min = 10 min. 54 
Question 29 of 30
29. Question
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Correct
Explanation:
Let the duration of the flight be x hours.
Then, 600 – 600 = 200 x x + (1/2) 600 – 1200 = 200 x 2x + 1 x(2x + 1) = 3
2x^{2} + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr. [neglecting the ve value of x]
Incorrect
Explanation:
Let the duration of the flight be x hours.
Then, 600 – 600 = 200 x x + (1/2) 600 – 1200 = 200 x 2x + 1 x(2x + 1) = 3
2x^{2} + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr. [neglecting the ve value of x]

Question 30 of 30
30. Question
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Correct
Explanation:
(1/2)x + (1/2)x = 10 21 24 x + x = 20 21 24 15x = 168 x 20
x = 168 x 20 = 224 km. 15 Incorrect
Explanation:
(1/2)x + (1/2)x = 10 21 24 x + x = 20 21 24 15x = 168 x 20
x = 168 x 20 = 224 km. 15